![Show that the maximum height and range of a projectile are u^2 sin^2theta2g and u^2 sin2thetag respectively Show that the maximum height and range of a projectile are u^2 sin^2theta2g and u^2 sin2thetag respectively](https://haygot.s3.amazonaws.com/questions/1215111_1239551_ans_4689b41414684d0c8f45f940a756ad82.png)
Show that the maximum height and range of a projectile are u^2 sin^2theta2g and u^2 sin2thetag respectively
![If u=f(x^3),v=g(x^2),f^(prime)(x)=cosx ,a n dg^(prime)(x)=sinx ,t h e n(d u)/(d v) is a)3/2xcosx^3cos e cx^2 b)2/3sinx^3secx^2 c)tanx (d) none of these If u=f(x^3),v=g(x^2),f^(prime)(x)=cosx ,a n dg^(prime)(x)=sinx ,t h e n(d u)/(d v) is a)3/2xcosx^3cos e cx^2 b)2/3sinx^3secx^2 c)tanx (d) none of these](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/645837892_web.png)
If u=f(x^3),v=g(x^2),f^(prime)(x)=cosx ,a n dg^(prime)(x)=sinx ,t h e n(d u)/(d v) is a)3/2xcosx^3cos e cx^2 b)2/3sinx^3secx^2 c)tanx (d) none of these
![Elements of plane and spherical trigonometry . 48 PLANE TRIGONOMETRY. Then OD = OG cos y, («) and DC= OG sin y. (/?) Further, since CD is perpendicular to OB, it Elements of plane and spherical trigonometry . 48 PLANE TRIGONOMETRY. Then OD = OG cos y, («) and DC= OG sin y. (/?) Further, since CD is perpendicular to OB, it](https://c8.alamy.com/comp/2CE0HFY/elements-of-plane-and-spherical-trigonometry-48-plane-trigonometry-then-od-=-og-cos-y-and-dc=-og-sin-y-further-since-cd-is-perpendicular-to-ob-it-makes-with-oaor-with-its-parallel-dh-an-angle-90-j-x-dg=-cd-cos-90-=-oc-sin-x-sin-by-and-39-also-d=-od-cos-odh=-od-cos-a-=-00-cos-a-cos-y-by-a-and-of=og-cos-y-now-taking-into-account-thedirections-in-which-the-severallines-are-measured-fig-18-of-=-okkf=-ed-dg-hence-substituting-for-of-edand-dg-the-values-found-abovewe-have-00-cos-x-j-y-=-og-cos-x-cos-y-og-sin-x-sin-y-cos-a-2CE0HFY.jpg)
Elements of plane and spherical trigonometry . 48 PLANE TRIGONOMETRY. Then OD = OG cos y, («) and DC= OG sin y. (/?) Further, since CD is perpendicular to OB, it
![Show that the maximum height and range of a projectile are u^2 sin^2theta2g and u^2 sin2thetag respectively Show that the maximum height and range of a projectile are u^2 sin^2theta2g and u^2 sin2thetag respectively](https://haygot.s3.amazonaws.com/questions/1353279_8494244d0a83482dbeea6abcdb6136fd.png)
Show that the maximum height and range of a projectile are u^2 sin^2theta2g and u^2 sin2thetag respectively
Show that the Maximum height and range of projectile are u^2sin^2θ/2g and u^2sin2θ/g respectively - Sarthaks eConnect | Largest Online Education Community
![Optimal angle for a projectile part 3: Horizontal distance as a function of angle (and speed) (video) | Khan Academy Optimal angle for a projectile part 3: Horizontal distance as a function of angle (and speed) (video) | Khan Academy](https://cdn.kastatic.org/ka-youtube-converted/-h_x8TwC1ik.mp4/-h_x8TwC1ik.png)